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copy_backward
Prototypetemplate <class BidirectionalIterator1, class BidirectionalIterator2> BidirectionalIterator2 copy_backward(BidirectionalIterator1 first, BidirectionalIterator1 last, BidirectionalIterator2 result); DescriptionCopy_backward copies elements from the range [first, last) to the range [result  (last  first), result) [1]. That is, it performs the assignments *(result  1) = *(last  1), *(result  2) = *(last  2), and so on. Generally, for every integer n from 0 to last  first, copy_backward performs the assignment *(result  n  1) = *(last  n  1). Assignments are performed from the end of the input sequence to the beginning, i.e. in order of increasing n. [2]The return value is result  (last  first) DefinitionDefined in the standard header algorithm, and in the nonstandard backwardcompatibility header algo.h.Requirements on types
Preconditions
ComplexityLinear. Exactly last  first assignments are performed.Examplevector<int> V(15); iota(V.begin(), V.end(), 1); copy_backward(V.begin(), V.begin() + 10, V.begin() + 15); Notes[1] Result is an iterator that points to the end of the output range. This is highly unusual: in all other STL algorithms that denote an output range by a single iterator, that iterator points to the beginning of the range. [2] The order of assignments matters in the case where the input and output ranges overlap: copy_backward may not be used if result is in the range [first, last). That is, it may not be used if the end of the output range overlaps with the input range, but it may be used if the beginning of the output range overlaps with the input range; copy has opposite restrictions. If the two ranges are completely nonoverlapping, of course, then either algorithm may be used. See alsocopy, copy_nCopyright © 1999 Silicon Graphics, Inc. All Rights Reserved. TrademarkInformation
