3.22.1 Interactive Interpreter Objects

runsource(source[, filename[, symbol]])

Compile and run some source in the interpreter. Arguments are the same as for compile_command(); the default for filename is '<input>', and for symbol is 'single'. One several things can happen:

The input is incorrect; compile_command() raised an exception (SyntaxError or OverflowError). A syntax traceback will be printed by calling the showsyntaxerror() method. runsource() returns 0.
The input is incomplete, and more input is required; compile_command() returned None. runsource() returns 1.
The input is complete; compile_command() returned a code object. The code is executed by calling the runcode() (which also handles run-time exceptions, except for SystemExit). runsource() returns 0.

The return value can be used to decide whether to use sys.ps1 or sys.ps2 to prompt the next line.

runcode(code): Execute a code object. When an exception occurs, showtraceback() is called to display a traceback. All exceptions are caught except SystemExit, which is allowed to propagate.
A note about KeyboardInterrupt: this exception may occur elsewhere in this code, and may not always be caught. The caller should be prepared to deal with it.

showsyntaxerror([filename]): Display the syntax error that just occurred. This does not display a stack trace because there isn't one for syntax errors. If filename is given, it is stuffed into the exception instead of the default filename provided by Python's parser, because it always uses '<string>' when reading from a string. The output is written by the write() method.

showtraceback(): Display the exception that just occurred. We remove the first stack item because it is within the interpreter object implementation. The output is written by the write() method.

write(data): Write a string to the standard error stream (sys.stderr). Derived classes should override this to provide the appropriate output handling as needed.

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